I found an enjoyable question on this topic: http://diendan.congdongcviet.com/showthread.php?t=85813
Create an custom menu in Window Context Menu, that I never thought. Get code of creator, I try to make menu.
After some minutes, I successfully create it. Then I have same question, how can get clicked file to my application. Try some ways and search Google. Yes, solution in here:
http://www.jfitz.com/tips/rclick_custom.html
Now, I will show you how to make a menu and do something with file.
For create new menu and remove it, I write a class:
1: public static class WindowContextMenu
2: {
3: public static void RemoveContextMenuItem(string extension, string menuName)
4: {
5: RegistryKey registryKey = Registry.ClassesRoot.OpenSubKey(extension);
6:
7: if (registryKey != null)
8: {
9: string extstring = registryKey.GetValue("").ToString(); //root
10:
11: registryKey.Close();
12:
13: if (!string.IsNullOrEmpty(extstring))
14: {
15: registryKey = Registry.ClassesRoot.OpenSubKey(extstring, true);
16: if (registryKey != null)
17: {
18: RegistryKey subky = registryKey.OpenSubKey("shell\\" + menuName);
19: if ( subky != null )
20: {
21: subky.Close();
22: registryKey.DeleteSubKeyTree("shell\\" + menuName);
23: registryKey.Close();
24: }
25: }
26: }
27: }
28: }
29:
30: public static void AddContextMenuItem(string extension, string menuName, string menuDescription, string menuCommand)
31: {
32: RegistryKey registryKey = Registry.ClassesRoot.OpenSubKey(extension);
33:
34: if (registryKey != null)
35: {
36: string extstring = registryKey.GetValue("").ToString(); //root
37:
38: registryKey.Close();
39:
40: if (!string.IsNullOrEmpty(extstring))
41: {
42: registryKey = Registry.ClassesRoot.OpenSubKey(extstring, true);
43:
44: if (registryKey != null)
45: {
46: string strkey = "shell\\" + menuName + "\\command";
47:
48: RegistryKey subky = registryKey.CreateSubKey(strkey);
49:
50: if (subky != null)
51: {
52: subky.SetValue("", menuCommand);
53: subky.Close();
54: }
55:
56: subky = registryKey.OpenSubKey("shell\\" + menuName, true);
57: if (subky != null)
58: {
59: subky.SetValue("", menuDescription);
60: subky.Close();
61: }
62: registryKey.Close();
63: }
64: }
65: }
66: }
67: }
1: private void btnRemove_Click(object sender, EventArgs e)
2: {
3: WindowContextMenu.RemoveContextMenuItem(".xls", "NewMenuOption");
4: }
5:
6: private void btnCreate_Click(object sender, EventArgs e)
7: {
8: WindowContextMenu.AddContextMenuItem(".xls", "NewMenuOption", "QuangHoang", Application.ExecutablePath + " \"%1\"");
9: }
So, now is the answer of question of topic I mention in top of post.
How your application open file?
You can use args parameter. When user click on your menu, you can run you application and send file path to. Your application get the path and do what you want. Like this:
1: static void Main(string[] args)
2: {
3: Application.EnableVisualStyles();
4: Application.SetCompatibleTextRenderingDefault(false);
5:
6: if (args != null && args.Length > 0)
7: {
8: Application.Run(new FormDemo(args[0]));
9: }
10: else Application.Run(new FormDemo());
11: }
How can get file's path user click on?
You can see on code I demo in above, you can see menuCommad parameter is Application.ExecutablePath + " \"%1\""
- First part is path of you application, you can set what you want
- Second part is "%1", it mean path of file you click on.
Source demo: http://www.mediafire.com/?qdg4ler3gt0guat
I think it so useful for some application.
Enjoy it :)
